World Scientific
Skip main navigation

Cookies Notification

We use cookies on this site to enhance your user experience. By continuing to browse the site, you consent to the use of our cookies. Learn More
×

System Upgrade on Tue, May 28th, 2024 at 2am (EDT)

Existing users will be able to log into the site and access content. However, E-commerce and registration of new users may not be available for up to 12 hours.
For online purchase, please visit us again. Contact us at customercare@wspc.com for any enquiries.
https://doi.org/10.1142/9789813275386_0016Cited by:0 (Source: Crossref)
Abstract:

In combinatorics we study the enumeration, combination, and permutations of sets of elements. Furthermore finite or countable discrete structures (for example finite sets, graphs) are studied. Enumerative combinatorics focuses on counting the number of certain combinatorial objects. A bijection of a finite set S onto itself is called a permutation of S. If S consist of n elements then there are n! possible permutations. The fundamental principle of counting tells us that if one event has j ∊ ℕ possible outcomes and a second independent event has k ∊ ℕ possible outcomes, then the number of possible outcomes for the combined events is given by j · k. Let S be a finite set with n elements. Then the number of subsets is 2n which includes the set S itself and the empty set. Let n ≥ 1, S be a set containing n elements and n1, …, nr be positive integers with n1+ n2+ … + nr = n. Then there exist

n!n1!n2!nr!n!n1!n2!nr!
different ordered partitions of S of the form (S1, S2,…, Sr), where S1 contains n1 elements, S2 contains n2 elements etc. Let A, B be two finite sets. The product set A×B of A and B is given by all ordered pairs (a, b), where aA and bB. If A has m elements and B has n elements, then A × B has m · n elements. Let n ≥ 1. The number of combinations C(n, r) of n objects taken r at the time is given by
C(n,r)=(nr)n!r!(nr)!.