Processing math: 76%
World Scientific
Skip main navigation

Cookies Notification

We use cookies on this site to enhance your user experience. By continuing to browse the site, you consent to the use of our cookies. Learn More
×

System Upgrade on Tue, May 28th, 2024 at 2am (EDT)

Existing users will be able to log into the site and access content. However, E-commerce and registration of new users may not be available for up to 12 hours.
For online purchase, please visit us again. Contact us at customercare@wspc.com for any enquiries.

A generalized trial equation scheme: A tool for solving thin films constructed from the ferroelectric materials

    https://doi.org/10.1142/S0217979224503089Cited by:10 (Source: Crossref)

    Abstract

    In this paper, the thin-film ferroelectric material equation (TFFME) which enables the propagation of solitary polarization in thin-film ferroelectric materials is investigated, and also illustrated through the nonlinear evolution equations. Ferroelectrics are dielectric materials that exhibit nonlinear behaviors in wave propagation. Thin films constructed from the ferroelectric materials are utilized in different modern electronic devices. To investigate the characteristics of new waves, the solitary wave dynamics of the mentioned equation is used in the generalized trial equation scheme. The bright and periodic solutions are obtained by semi-inverse variational principle scheme. Many alternative responses may be obtained through different formulae; each of these solutions offers a distinct graph. The validity of such methods and solutions may be demonstrated by assessing how well the relevant techniques and solutions match up. The effects of free variables on the behavior of few achieved solutions for nonlinear rational exact cases are also plotted and explored depending upon the nature of nonlinearities. The dynamic properties of the obtained results are shown and analyzed by some density, two- and three-dimensional images. The results provide a way for future research on generating optical memories based on the nonlinear solitons.

    1. Introduction

    Numerous branches of nonlinear sciences including plasma physics, geochemistry, solid-state physics, fluid mechanics, optical fibers, nuclear physics and chemical physics have been studied through nonlinear evolution equations (NLEEs). According to the objectives of many researchers, traveling wave solutions for NLEEs can be investigated using a number of analytical and numerical techniques to get the exact solutions for them, such as in the fabrication of a composite membrane,1 the generalized Burgers equation with variable coefficients,2 the modulation of electronic properties in spintronic interfaces,3 the characteristic values for fiber/matrix adhesion,4 the (2+1)-dimensional variable-coefficient Caudrey–Dodd–Gibbon–Kotera–Sawada equation,5 the creep behavior of single-lap adhesive joints,6 the random decrement signature technique and artificial neural network algorithm,7 the ferroelectricity due to symmetry-breaking phase transition,8 the nonlinear vibration and dispersive wave systems,9 a hybrid power system,10 a Ferrotoroidic with well-separated spin chains,11 the Konopelchenko–Dubrovsky equation,12 the (3+1)D Burgers system,13 He’s variational direct methods for the KP–BBM equation,14 the cubic–quintic nonlinear Helmholtz equation,15 the probabilistic decomposition-based security,16 the extended sinh-Gordon equation expansion method,17 ranking extreme efficient decision-making units method,18 the new (G/G)-expansion method,19 the finite element method,20 generalized nonlinear wave equation in a liquid with gas bubbles,21 the generalized Hietarinta equation,22 the design and analysis of a torsional-mode microelectromechanical system23 and generalized shallow water wave equation.24

    Ferroelectric thin films have become a potential choice in the field of detection with ultraviolet photodetectors due to their wide bandgap and unique photovoltaic aspects. Additionally, ferroelectric thin films have excellent dielectric, piezoelectric, pyroelectric, acousto-optic effects, etc.25 Reference 26 showed that the growth of ferroelectric layer on the original perovskite grains can reduce the formation of grain boundaries and hence minimize the recombination of electron and hole at the grain boundaries. The solitary wave dynamics of the thin-film ferroelectric material equation (TFFME) was investigated in Ref. 27. Umoh et al. designed materials exhibiting the combined properties such as ferroelectricity, ferromagnetism and ferroelasticity at the same phase for nanoelectronic devices based on oxide films.28 An analysis of the thermal and ferroelectric properties of an Ising thin film in a transverse field extended for a higher spin within the quantum Monte Carlo method, was provided in Ref. 29. Ferroelectric thin films have demonstrated great potential in electrocaloric solid-state refrigeration on account of large adiabatic temperature changes.28 Reference 30 demonstrated ferroelectric tunnel junctions whose conductivity varies linearly and symmetrically by judiciously combining ferroelectric domain switching and oxygen vacancy migration.

    First, we give the solitary wave behavior of polarization for ferroelectric materials concerning the TFFME11 in one-dimensional form as follows :

    mT22ut2[(p22μ)u+p4u3+p6u5]JΔu=0,(1)
    where mass and charge density are m and u, T,p2,p4 and p6 are the temperature and pressures. Also, J denotes the space inhomogeneity coefficient and μ is the reciprocal of electric susceptibility.31 The ferroelectric material was subjected to a standing electric field which inhibits remanent polarization and facilitates the access to the instantaneous polarization.31 Two distinct techniques have been applied to get the accurate solutions for the thin-film ferroelectric material equation which plays a vital role in optics with respect to waves propagating through ferroelectric materials.32 Moreover, the Paul–Painlevé approach that discovered surprising results was used to achieve the optical soliton solutions of the thin-film ferroelectric material equation. 33

    Soliton theory is a very efficient and competent way to describe nonlinear features. Soliton theory involves two basic routes to study and explain nonlinear features. Soliton solutions are visible in the analysis of numerous nonlinear subjects. Soliton is an extremely thin, high-intensity light pulse. Solitons have the most remarkable properties of both particles and waves that can reflect the nonlinear features in a well-organized and competent way. Studying the nature by framing nonlinear evolution equations along with their soliton solutions is quicker and unquestionable. Solitons keep their velocities, shapes and amplitudes unchanged even after interacting with others due to their perfectly elastic interaction. In this paper, some solutions, including soliton, bright soliton, singular-soliton and periodic wave solutions, by the generalized trial equation scheme (GTES) were also obtained. These results show that the auxiliary methods are powerful mathematical tools to handle the nonlinear integrable equations from nature. Finding precise solutions is crucial for understanding the fundamental properties of these phenomena, particularly for soliton and energy storage systems34 and a combined energy system.35 Numerous researchers lately discovered the analytical traveling-wave formulations of NLPDEs which play an important function in different methods such as image processing and flow field reconstruction algorithm,36 the van der Waals equation for the acid–base theory of surfaces,37 the probabilistic decomposition-based security,16 robust optimization technique,38 the demand response and improved water wave optimization algorithm,39 the hybrid forecast engine-based intelligent algorithm,40 the hybrid convolutional neural network and extreme learning machine,41 amended Dragon Fly optimization algorithm,42 a hybrid robust–stochastic approach43 and correlation of random variables with Copula theory.44

    The nonlinear effects on dynamical features of soliton waves in a nonlinear Schrödinger equation were analyzed with dark soliton solutions.45 Authors46 investigated the dynamics of soliton waves in a generalized nonlinear Schrödinger equation applying the modified Jacobi elliptic expansion method. The nonsingular multi-complexion wave and multi-shock wave for a generalized KdV equation were studied using the principle of linear superposition with the help of symbolic computations.47 Both compressive and rarefactive subsonic solitary waves were found depending on the wave speeds in various directions of propagation.48 The hyperbolic, exponential, trigonometric functions, other soliton solutions and their combinations for the cold bosonic atoms in a zigzag optical lattice model have been obtained based on the generalized Riccati equation mapping method and generalized Kudryashov method.49 Abundant exact solitary solutions including multiple-soliton, bell-shaped soliton, traveling wave, trigonometric and rational solutions have been constructed by applying the generalized exponential rational function method to the strain wave equation in microstructured solids.50 The Lie group of point transformation method to construct the generalized invariant solutions for the (2+1)-dimensional dispersive long-wave equations under some constraints was studied in Ref. 51. This work successfully applied the generalized trial equation approach with a homogeneous balancing principle to TFFME in (1+1) dimensions with constant coefficients for obtaining the spatiotemporal soliton solutions and exact extended traveling-wave solutions.

    Inspired by the previous works, the aim of this paper is to investigate the solitons and other forms of solutions by a generalized trial equation scheme. The outline of the paper is as follows. In Sec. 2, the TFFME for the nonlinear ordinary differential equation is obtained by transformation. Furthermore, in Secs. 3 and 4, different forms of solitary wave solutions are established by the generalized trial equation scheme. Finally, the conclusions are provided in Sec. 5.

    2. Transforming PDE to ODE

    For Eq. (1), let x and t be the longitudinal and transverse coordinates. Using the next wave transformation u(x,t)=u(η),η=xλt, where λ is an arbitrary constant to be determined through the method’s steps, leads to the following ODE :

    (mλ2T2J)u[(p22μ)u+p4u3+p6u5]=0,(2)
    where the wave speed is denoted by λ. By using the balancing principle on the terms of Eq. (3) between ψ and ψ5 leads to k+2=5k, then k=1/2. By utilizing the transformation u(η)=ψ(η), Eq. (2), with respect to η and zero-integration constant, becomes
    (mλ2T2J)(14ψ2+12ψψ)(p22μ)ψ2p4ψ3p6ψ4=0.(3)
    Applying the balancing principle to the terms of Eq. (3) between ψ and ψ4 leads to k=1.

    3. Generalized Trial Equation Scheme

    Handling the investigated model through the generalized trial equation scheme52 involves the following steps, as mentioned earlier:

    Step 1. In this step, we have

    𝒮1(F,Fx,Ft,Fxx,Ftt,)=0,(4)
    where 𝒮 is a polynomial of F and its partial derivatives.

    Step 2. Utilizing the traveling-wave transformation

    ξ=θ1x+θ2t+p1,(5)
    where θ1 and θ2 are the nonzero arbitrary values, allows to reduce Eq. (4) into an ODE of F=F(ξ) with the following form :
    𝒮2(F,θ1F,θ2F,θ21F,θ22F,)=0.(6)
    Step 3. The generated solution of (4) is given as
    F(ξ)=ai=0AiΩi+ai=1BiΩi,(7)
    where
    (Ω)2=Q(Ω)=Q1(Ω)Q2(Ω)=ϕbΩb++ϕ1Ω+ϕ0φcΩc++φ1Ω+φ0.(8)
    Using Eqs. (7) and (8), the following derivatives are obtained :
    (F)2=Q1(Ω)Q2(Ω)(ai=1iAiΩi1ai=1iBiΩi1)2,(9)
    F=Q1(Ω)Q2(Ω)Q1(Ω)Q2(Ω)2Q22(Ω)(ai=1iAiΩi1ai=1iBiΩi1)+Q1(Ω)Q2(Ω)(ai=2i(i1)AiΩi1+ai=1i(i+1)BiΩi2),(10)
    where Q1(Ω) and Q2(Ω) are polynomials. Appending these equations into Eq. (4) results in an equation of the polynomial Φ(Ω) of Ω,
    Φ(Ω)=ωsΩs++ω1Ω+ω0=0.(11)
    By utilizing the balancing principle on (11), the relations of a,b and c are discovered. We can take some values of a,b and c.

    Step 4. Each coefficient of polynomial Λ(Γ) is substituted with zero to derive an algebraic system as follows :

    ωi=0,i=1,2,,s.(12)
    By solving the above system (12), the parameters namely ϕ0,ϕ1,,ϕb, φ0,φ1,,φc and ω0,ω1,,ωa are obtained.

    Step 5. In this step, the elementary form of the integral by reduction of Eq. (8) is reached as follows :

    ±(ξξ0)=dΩQ(Ω)=Q2(Ω)Q1(Ω)dΩ,(13)
    where ξ0 is a free constant.

    4. Application of GTES

    In this section, we consider Eq. (1). Then, by balancing the terms FF or F2 with F4 of Eq. (3), and by determining the values of a,b and c, we can get

    2a=bc2.(14)
    For diverse values of the parameters of a,b and c, we obtain two cases as discussed below.

    4.1. Case I: a=1,b=4 and c=0

    If we consider a=1,b=4 and c=0 in Eqs. (7) and (8), then we obtain

    F(ξ)=A0+A1Ω+B1Ω1,(15)
    (F(ξ))2=ϕ4Ω4+ϕ3Ω3+ϕ2Ω2+ϕ1Ω+ϕ0ρ0(A1B1Ω2)2,(16)
    where ϕ40 and ρ00. Solving the algebraic equation (12) yields different results.

    The different sets of categories of solutions are discussed in the following subsections.

    4.1.1. Set I

    Here we have

    A0=A1=ϕ4=0,ϕ1=3/2p4ϕ0B1p6,ϕ2=3ϕ0(p2+2μ)B21p6,ρ0=3/4ϕ0(JT2mλ2)T2B21p6,ϕ3=ϕ3.(17)
    Substituting these results into Eqs. (8) and (15) results in
    ±(ξξ0)=ρ0ϕ3dΩΩ3+ϕ2ϕ3Ω2+ϕ1ϕ3Ω+ϕ0ϕ3=3/4ϕ0(JT2mλ2)T2B21p6ϕ3dΩΩ33ϕ0(p2+2μ)B21p6ϕ3Ω2+3/2p4ϕ0B1p6ϕ3Ω+ϕ0ϕ3.(18)
    Integrating (18), the following solutions to Eq. (1) are attained:

    First solution. Let

    ±(ξξ0)=2ρ0ϕ3Ωr1(Ωr1)3,ρ0=3/4ϕ0(JT2mλ2)T2B21p6,(19)
    then the relation (19) results in
    Ω=(ξξ0)2ϕ3r1+4ρ0ϕ3(ξξ0)2,(20)
    ±(ξξ0)=2ρ0ϕ3(Ωr1)Ωr2(Ωr1)2(Ωr2)r1+r2arctan(Ωr2r1+r2),(21)
    ±(ξξ0)=2ρ0ϕ3r1+r2Ω3Ω2r1Ω2r2Ω2r3+Ωr1r2+Ωr1r3+Ωr2r3r1r2r3×Ωr1r1+r2Ωr3r1r3Ωr2r1r2×EllipticF(Ωr1r1+r2,r1r2r1r3),(22)
    then the relation (22) results in
    Ω=(JacobiSN(1/2ρ0ϕ3(r1r3)(ξξ0)ρ0,r1r2r1r3))2(r1r2)+r1,ρ0=3/4ϕ0(JT2mλ2)T2B21p6.(23)
    Moreover, the parameters r1,r2 and r3 are the roots of the polynomial equation
    Ω3+ϕ2ϕ3Ω2+ϕ1ϕ3Ω+ϕ0ϕ3=0.(24)
    Putting the solutions (20) and (23) into (15), the following traveling-wave solutions of Eq. (1), respectively, are attained :
    u1(x,t)={B1ϕ3(xλtξ0)2(xλtξ0)2ϕ3r1ϕ0(JT2mλ2)T2B21p6}12,(25)
    u2(x,t)={B1(JacobiSN(ϕ3(r1r3)(xλtξ0)3ϕ0(JT2mλ2)T2B21p6,r1r2r1r3))2×(r1r2)+r1}12.(26)

    4.1.2. Set II

    Here we have

    A1=0,ϕ1=1/2ϕ0(8A0p6+3p4)B1p6,ϕ2=3/2ϕ0(4A20p63A0p4+4μ2p2)B21p6,ϕ4=ϕ4,ϕ3=3A20ϕ0(A20p6A0p4+2μp2)B41p6ϕ4A0B31p6,ρ0=3/4ϕ0(JT2mλ2)T2B21p6.(27)
    Substituting these results into Eqs. (8) and (27), we can get
    ±(ξξ0)=K0dΩΩ4+ϕ3ϕ4Ω3+ϕ2ϕ4Ω2+ϕ1ϕ4Ω+ϕ0ϕ4,K0=3/4ϕ0(JT2mλ2)T2B21p6ϕ4.(28)
    Integrating  (28), the below solutions are obtained:

    First solution. Let

    ±(ξξ0)=3/4ϕ0(JT2mλ2)T2B21p6ϕ4Ωr1,Ω4+ϕ3ϕ4Ω3+χ2(ϕ)Ω2+χ1(ϕ)Ω+ϕ0ϕ4=(Ωr1)4,χ1(ϕ)=1/2ϕ0(8A0p6+3p4)B1p6ϕ4,χ2(ϕ)=3/2ϕ0(4A20p63A0p4+4μ2p2)B21p6ϕ4,χ3(ϕ)=3A20ϕ0(A20p6A0p4+2μp2)B41p6ϕ4A0B31p6ϕ4.(29)
    Therefore, the exact solution will be
    u1(x,t)={A0+B1(xλtξ0)r1(xλtξ0)3/4ϕ0(JT2mλ2)T2B21p6ϕ4}12,(30)
    where θ1,θ2,θ4,B1,p1 and p2 can be selected as free constants.

    Second solution. Let

    ±(ξξ0)=3/4ϕ0(JT2mλ2)T2B21p6ϕ4r1r2ln|Ωr1Ωr2|Ω=r2+(r1r2)K01exp((ξξ0)(r1r2)),(31)
    Ω4+ϕ3ϕ4Ω3+χ2(ϕ)Ω2+χ1(ϕ)Ω+ϕ0ϕ4=(Ωr1)2(Ωr2)2ϕ3=2(r1+r2)ϕ4,χ2(ϕ)=r21+4r1r2+r22,χ1(ϕ)=2r1r2(r1+r2),ϕ0=r21r22ϕ4.(32)
    Hence, the solution is given as
    u2(x,t)={A0+B1r2+(r1r2)3/4ϕ0(JT2mλ2)T2B21p6ϕ41exp[(xλt+p2ξ0)(r1r2)]}12,(33)
    where θ1,θ2,θ4,B1,p1 and p2 can be selected as free constants.

    Third solution. Let

    ±(ξξ0)=3/4ϕ0(JT2mλ2)T2B21p6ϕ4(r1r2)(r1r3)ln|(r1r3)(Ωr2)(r1r2)(Ωr3)(r1r3)(Ωr2)+(r1r2)(Ωr3)|,(34)
    Ω=r1(r1r2)(r1r3)2r1r2r3+(r3r2)cosh[(r1r2)(r1r3)3/4ϕ0(JT2mλ2)T2B21p6ϕ4(ξξ0)],(35)
    Ω4+ϕ3ϕ4Ω3+χ2(ϕ)Ω2+χ1(ϕ)Ω+ϕ0ϕ4=(Ωr1)2(Ωr2)(Ωr3)ϕ3=(2r1+r2+r3)ϕ4,χ2(ϕ)=r21+2r1r2+2r1r3+r2r3,χ1(ϕ)=r21r2r21r32r1r2r3,ϕ0=r21r2r3ϕ4ϕ4.(36)
    Therefore, the solution will be
    u3(x,t)={A0+B1r1(r1r2)(r1r3)2r1r2r3+(r3r2)cosh[(r1r2)(r1r3)3/4ϕ0(JT2mλ2)T2B21p6ϕ4(xλtξ0)]}12,(37)
    where θ1,θ2,θ4,A0,B1,p1 and p2 can be selected as free constants.

    Fourth solution. Let

    ±(ξξ0)=3ϕ0(JT2mλ2)T2B21p6ϕ4(r1r3)(r2r4)G(φ,σ),r1>r2>r3>r4,(38)
    where
    G(φ,σ)=φ0dψ1l2sin2ψ,φ=arcsin(r2r4)(Ωr1)(r1r4)(Ωr2),σ2=(r2r3)(r1r4)(r1r3)(r2r4),Ω=r2+(r1r2)(r4r2)r4r2+(r1r4)sn2[(r1r3)(r2r4)2K0(ξξ0),(r2r3)(r1r4)(r1r3)(r2r4)],(39)
    Ω4+ϕ3ϕ4Ω3+χ2(ϕ)Ω2+χ1(ϕ)Ω+ϕ0ϕ4=(Γα1)(Γα2)(Γα3)(Γα4)(40)
    ϕ3=(r1+r2+r3+r4)ϕ4,χ2(ϕ)=r1r2+r1r3+r1r4+r2r3+r2r4+r3r4,χ1(ϕ)=r1r2r3r1r2r4r1r3r4r2r3r4,ϕ0=r1r2r3r4ϕ4.(41)
    Therefore, the solution will be
    u4(x,t)={A0+B1r2+(r1r2)(r4r2)r4r2+(r1r4)sn2[(r1r3)(r2r4)3ϕ0(JT2mλ2)T2B21p6ϕ4(xλtξ0),(r2r3)(r1r4)(r1r3)(r2r4)]}12.(42)

    Remark 1. If the modulus σ1, then the solution can be reduced to the solitary wave solution

    u5(x,t)={A0+B1r2+(r1r2)(r4r2)r4r2+(r1r4)tanh2[(r1r4)(r2r4)3ϕ0(JT2mλ2)T2B21p6ϕ4(xλtξ0)]}12,(43)
    where r3=r4.

    Remark 2. If the modulus σ0, then the solution can be reduced to the solitary wave solution

    u6(x,t)={A0+B1r3+(r1r3)(r4r3)r4r3+(r1r4)sin2[(r1r3)(r3r4)3ϕ0(JT2mλ2)T2B21p6ϕ4(xλtξ0)]}12,(44)
    where r2=r3.

    Figure 1 depicts the impact analysis of singular-soliton solution where the plots of u are given for the following values for Eq. (46) :

    λ=4,p6=3,m=2,T=3,μ=2,J=2,ϕ4=2,A0=4,B1=3,(45)
    u=24742(7296t+24x)1.(46)
    The behavior of general singular solitons received from the mentioned technique is investigated, which is presented in Fig. 1. From this figure, it is ostensible that the singular solitons exhibit a stable propagation for the thin-film equation.

    Fig. 1.

    Fig. 1. (Color online) Plots of singular-soliton solution (46) (u1) for the thin-film ferroelectric material equation.

    Also, the effect on kink–singular-soliton solution u is analyzed and plotted in Fig. 2 with the following values for Eq. (48) :

    λ=4,p6=3,m=2,T=3,μ=2,J=2,r1=2,ϕ4=2,A0=1,B1=5,(47)
    u=73/442(15+15e28t+7x+772)1.(48)
    The dynamics of general kink–singular solitons received from the mentioned technique is investigated, which is presented in Fig. 2. From the figure, it is ostensible that the solitons exhibit a stable propagation in both components of thin-film ferroelectric material equation.

    Fig. 2.

    Fig. 2. (Color online) Plots of kink soliton solution (48) (u2) for the thin-film ferroelectric material equation.

    Also, the effect on kink–singular-soliton solution u is analyzed and plotted in Fig. 3 with the following values for Eq. (50) :

    λ=4,p6=3,m=2,T=3,μ=2,J=2,r1=2,r3=4,ϕ4=2,A0=3,B1=1,(49)
    u=1/2147+13cosh(6t3/2x)8+13cosh(6t3/2x).(50)
    The behavior of general two solitons received from the mentioned technique is investigated, which is presented in Fig. 3. From the figure, it is obvious that the solitons exhibit a stable propagation for the thin-film ferroelectric material equation.

    Fig. 3.

    Fig. 3. (Color online) Plots of kink soliton solution (50) (u3) for the thin-film ferroelectric material equation.

    Also, the effect on kink–singular-soliton solution u is analyzed and plotted in Fig. 4 with the following values for Eq. (52) :

    λ=2,p6=3,m=2,T=3,μ=2,J=2,r2=2,r3=r4=4,ϕ4=2,A0=2,B1=5,(51)
    u=3/2132(cosh(3/8(2tx)132))2118(cosh(3/8(2tx)132))213.(52)
    The behavior of general bright solitons received from the mentioned scheme is investigated, which is presented in Fig. 4. From the figure, it is ostensible that the solitons exhibit a stable propagation for the thin-film ferroelectric material equation.

    Fig. 4.

    Fig. 4. (Color online) Plots of bright soliton solution (52) (u4) for the thin-film ferroelectric material equation.

    Also, the effect on periodic wave solution u is analyzed and plotted in Fig. 5 with the following values for Eq. (54) :

    λ=2,p6=3,m=2,T=3,μ=2,J=2,r2=r3=4,r4=4,ϕ4=5,A0=2,B1=5,(53)
    u=1331((cos((6t3x)132540))21)(12(cos((6t3x)132540))213)1.(54)
    The behavior of general periodic wave received from the mentioned technique is investigated, which is presented in Fig. 5. From the figure, it is ostensible that the periodic structure exhibits a stable propagation for the thin-film ferroelectric material equation.

    Fig. 5.

    Fig. 5. (Color online) Plots of periodic wave solution (54) (u5) for the thin-film ferroelectric material equation.

    4.1.3. Set III

    Here we have

    B1=0,ϕ1=3A20ϕ4(A20p6A0p4+2μp2)A41p6ϕ0A0A31p6,ϕ2=3/2ϕ4(4A20p63A0p4+4μ2p2)A21p6,ϕ4=ϕ4,ϕ3=1/2ϕ4(8A0p6+3p4)A1p6,ρ0=3/4ϕ4(JT2mλ2)T2A21p6.(55)
    Substituting these results into Eqs. (8) and (55), we get
    ±(ξξ0)=K0dΩΩ4+ϕ3ϕ4Ω3+ϕ2ϕ4Ω2+ϕ1ϕ4Ω+ϕ0ϕ4,K0=3/4(JT2mλ2)T2A21p6.(56)
    Integrating  (56), the below solutions are obtained:

    First solution. Let

    ±(ξξ0)=3/4(JT2mλ2)T2A21p6Ωr1,Ω4+ϕ3ϕ4Ω3+χ2(ϕ)Ω2+χ1(ϕ)Ω+ϕ0ϕ4=(Ωr1)4,χ1(ϕ)=3A20(A20p6A0p4+2μp2)A41p6ϕ0A0A31p6,χ2(ϕ)=3/2ϕ4(4A20p63A0p4+4μ2p2)A21p6ϕ4,χ3(ϕ)=1/2(8A0p6+3p4)A1p6.(57)
    Therefore, the exact solution will be
    u1(x,t)={A0+r1A13/4(JT2mλ2)T2A21p6xλtx0}12,(58)
    where θ1,θ2,θ4,B1,p1 and p2 can be selected as free constants.

    Second solution. Let

    ±(ξξ0)=3/4(JT2mλ2)T2A21p6r1r2ln|Ωr1Ωr2|Ω=r2+(r1r2)3/4(JT2mλ2)T2A21p61exp((ξξ0)(r1r2)),(59)
    Ω4+ϕ3ϕ4Ω3+χ2(ϕ)Ω2+χ1(ϕ)Ω+ϕ0ϕ4=(Ωr1)2(Ωr2)2ϕ3=2(r1+r2)ϕ4,χ2(ϕ)=r21+4r1r2+r22,χ1(ϕ)=2r1r2(r1+r2),ϕ0=r21r22ϕ4.(60)
    Hence, the solution will be
    u2(x,t)={A0+A1r2+A1(r1r2)3/4(JT2mλ2)T2A21p61exp((xλtξ0)(r1r2))}12,(61)
    where θ1,θ2,θ4,B1,p1 and p2 can be selected as free constants.

    Third solution. Let

    ±(ξξ0)=3/4(JT2mλ2)T2A21p6(r1r2)(r1r3)ln|(r1r3)(Ωr2)(r1r2)(Ωr3)(r1r3)(Ωr2)+(r1r2)(Ωr3)|,(62)
    Ω=r1(r1r2)(r1r3)2r1r2r3+(r3r2)cosh[(r1r2)(r1r3)3/4(JT2mλ2)T2A21p6(xλtξ0)],(63)
    Ω4+ϕ3ϕ4Ω3+χ2(ϕ)Ω2+χ1(ϕ)Ω+ϕ0ϕ4=(Ωr1)2(Ωr2)(Ωr3)ϕ3=(2r1+r2+r3)ϕ4,χ2(ϕ)=r21+2r1r2+2r1r3+r2r3,χ1(ϕ)=r21r2r21r32r1r2r3,ϕ0=r21r2r3ϕ4ϕ4.(64)
    Therefore, the solution will be
    u3(x,t)={A0+A1r1A1(r1r2)(r1r3)2r1r2r3+(r3r2)cosh[(r1r2)(r1r3)3/4(JT2mλ2)T2A21p6(xλtξ0)]}12,(65)
    where θ1,θ2,θ4,A0,B1,p1 and p2 can be selected as free constants.

    Fourth solution. Let

    ±(ξξ0)=3/4(JT2mλ2)T2A21p6(r1r3)(r2r4)G(φ,σ),r1>r2>r3>r4,(66)
    where
    G(φ,σ)=φ0dψ1l2sin2ψ,φ=arcsin(r2r4)(Ωr1)(r1r4)(Ωr2),σ2=(r2r3)(r1r4)(r1r3)(r2r4),Ω=r2+(r1r2)(r4r2)r4r2+(r1r4)sn2[(r1r3)(r2r4)3(JT2mλ2)T2A21p6(ξξ0),(r2r3)(r1r4)(r1r3)(r2r4)],(67)
    Ω4+ϕ3ϕ4Ω3+χ2(ϕ)Ω2+χ1(ϕ)Ω+ϕ0ϕ4=(Γα1)(Γα2)(Γα3)(Γα4)(68)
    ϕ3=(r1+r2+r3+r4)ϕ4,χ2(ϕ)=r1r2+r1r3+r1r4+r2r3+r2r4+r3r4,χ1(ϕ)=r1r2r3r1r2r4r1r3r4r2r3r4,ϕ0=r1r2r3r4ϕ4.(69)
    Therefore, the solution will be
    u4(x,t)={A0+A1r2+A1×(r1r2)(r4r2)r4r2+(r1r4)sn2[(r1r3)(r2r4)3(JT2mλ2)T2A21p6(ξξ0),(r2r3)(r1r4)(r1r3)(r2r4)]}12.(70)

    Remark 1. If the modulus σ1, then the solution can be reduced to the solitary wave solution

    u5(x,t)={A0+A1r2+A1×(r1r2)(r4r2)r4r2+(r1r4)tanh2[(r1r4)(r2r4)3(JT2mλ2)T2A21p6(xλtξ0)]}12,(71)
    where r3=r4.

    Remark 2. If the modulus σ0, then the solution can be reduced to the solitary wave solution

    u6(x,t)={A0+A1r2+A1×(r1r3)(r4r3)r4r2+(r1r4)sin2[(r1r3)(r3r4)3(JT2mλ2)T2A21p6(ξξ0)]}12,(72)
    where r2=r3.

    Figure 6 depicts the impact on singular-soliton solution u for the following values for Eq. (74) :

    λ=4,p6=3,m=2,T=3,μ=2,J=2,ϕ4=2,B1=3,(73)
    u=1/33144t1436x14+10368t25184tx+648x2+7(4tx)(72t18x+14).(74)
    The behavior of general singular solitons received from the mentioned technique is investigated, which is presented in Fig. 6. From the figure, it is ostensible that the singular solitons exhibit a stable propagation for the thin-film equation.

    Fig. 6.

    Fig. 6. (Color online) Plots of singular-soliton solution (74) (u1) for the thin-film ferroelectric material equation.

    Also, the effect on kink–singular-soliton solution u is analyzed and plotted in Fig. 7 with the following values for Eq. (76) :

    λ=4,p6=3,m=2,T=3,μ=2,J=2,r1=2,ϕ4=2,A0=1,B1=5,(75)
    u=1/2260e6t3/2x72+1800e12t3x60723600e6t3/2x+1807(1+e6t3/2x)(40+40e6t3/2x+72).(76)
    The dynamics of general kink–singular solitons received from the mentioned technique is investigated, which is presented in Fig. 7. From the figure, it is ostensible that the solitons exhibit a stable propagation in both components of thin-film ferroelectric material equation.

    Fig. 7.

    Fig. 7. (Color online) Plots of kink soliton solution (76) (u2) for the thin-film ferroelectric material equation.

    Figure 8 depicts the impact on kink–singular-soliton solution u for the following values for Eq. (78) :

    λ=4,p6=3,m=2,T=3,μ=2,J=2,r1=2,r3=4,ϕ4=2,A0=3,B1=1,(77)
    u=2(1101261+1154cosh(3/7(4tx)73+101261)+4335)2(577cosh(3/7(4tx)73+101261)+2417+601261)(577cosh(3/7(4tx)73+101261)+1419+401261).(78)
    The behavior of general two solitons received from the mentioned technique is investigated, which is presented in Fig. 8. From the figure, it is obvious that the solitons exhibit a stable propagation for the thin-film ferroelectric material equation.

    Fig. 8.

    Fig. 8. (Color online) Plots of two-soliton solution (78) (u3) for the thin-film ferroelectric material equation.

    Also, the effect on bright soliton solution u is analyzed and plotted in Fig. 9 for the following values for Eq. (80) :

    λ=2,p6=3,m=2,T=3,μ=2,J=2,r2=2,r3=r4=4,ϕ4=2,A0=2,B1=5,(79)
    u=0.0007(35120000000Ω2+376500000000)2(5017000000Ω2+145580000000)(37720000Ω2+128400000),(80)
    Ω=tan(1.34t0.671x).
    The behavior of general bright solitons received from the mentioned scheme is investigated, which is presented in Fig. 9. From the figure, it is ostensible that the solitons exhibit a stable propagation for the thin-film ferroelectric material equation.

    Fig. 9.

    Fig. 9. (Color online) Plots of bright soliton solution (80) (u4) for the thin-film ferroelectric material equation.

    Also, the effect on periodic wave solution u is analyzed and plotted in Fig. 10 for the following values for Eq. (82) :

    λ=2,p6=3,m=2,T=3,μ=2,J=2,r2=r3=4,r4=4,ϕ4=5,A0=2,B1=5,(81)
    u=1/1262(554778S2215513209277389)2(237762S2118881103413209)(26418S2132092913209),S=sin((3tx)1077360).(82)
    The behavior of general periodic wave received from the mentioned technique is investigated, which is presented in Fig. 10. From the figure, it is ostensible that the periodic structure exhibits a stable propagation for the thin-film ferroelectric material equation.

    Fig. 10.

    Fig. 10. (Color online) Plots of periodic wave solution (82) (u5) for the thin-film ferroelectric material equation.

    4.1.4. Set IV

    Here we have

    A1=1/4A20B1,ϕ1=1/2ϕ0(8A0p6+3p4)B1p6,ϕ2=3/2ϕ0(5A20p63A0p4+4μ2p2)B21p6,ϕ4=1/16A40ϕ0B41,ϕ3=1/8A20ϕ0(8A0p6+3p4)B31p6,ρ0=3/4ϕ0(JT2mλ2)T2B21p6.(83)
    Substituting these results into Eqs. (8) and (83), we get
    ±(ξξ0)=K0dΩΩ4+ϕ3ϕ4Ω3+ϕ2ϕ4Ω2+ϕ1ϕ4Ω+ϕ0ϕ4,K0=12(JT2mλ2)B21T2p6A40.(84)

    Integrating (84), the below solutions are obtained:

    First solution. Let

    ±(ξξ0)=12(JT2mλ2)B21T2p6A40Ωr1,Ω4+ϕ3ϕ4Ω3+χ2(ϕ)Ω2+χ1(ϕ)Ω+ϕ0ϕ4=(Ωr1)4,χ1(ϕ)=8(8A0p6+3p4)B31p6A40,χ2(ϕ)=24(5A20p63A0p4+4μ2p2)B21p6A40,χ3(ϕ)=2(8A0p6+3p4)B1A20p6.(85)
    Therefore, the exact solution will be
    u1(x,t)={A0+A204B1r1A204B112(JT2mλ2)B21T2p6A40xλtx0+B1r112(JT2mλ2)B21T2p6A40xλtx0}12,(86)
    where θ1,θ2,θ4,B1,p1 and p2 can be selected as free constants.

    Second solution. Let

    ±(ξξ0)=12(JT2mλ2)B21T2p6A40r1r2ln|Ωr1Ωr2|Ω=r2+(r1r2)12(JT2mλ2)B21T2p6A401exp((ξξ0)(r1r2)),(87)
    Ω4+ϕ3ϕ4Ω3+χ2(ϕ)Ω2+χ1(ϕ)Ω+ϕ0ϕ4=(Ωr1)2(Ωr2)2ϕ3=2(r1+r2)ϕ4,χ2(ϕ)=r21+4r1r2+r22,χ1(ϕ)=2r1r2(r1+r2),ϕ0=r21r22ϕ4.(88)
    Hence, the solution will be
    u2(x,t)={A0+A204B1r2+A204B1(r1r2)12(JT2mλ2)B21T2p6A401exp((xλtξ0)(r1r2))+B1r2+(r1r2)12(JT2mλ2)B21T2p6A401exp((xλtξ0)(r1r2))}12,(89)
    where θ1,θ2,θ4,B1,p1 and p2 can be selected as free constants.

    Third solution. Let

    ±(ξξ0)=12(JT2mλ2)B21T2p6A40(r1r2)(r1r3)ln|(r1r3)(Ωr2)(r1r2)(Ωr3)(r1r3)(Ωr2)+(r1r2)(Ωr3)|,(90)
    Ω=r1(r1r2)(r1r3)2r1r2r3+(r3r2)cosh[(r1r2)(r1r3)12(JT2mλ2)B21T2p6A40(xλtξ0)],(91)
    Ω4+ϕ3ϕ4Ω3+χ2(ϕ)Ω2+χ1(ϕ)Ω+ϕ0ϕ4=(Ωr1)2(Ωr2)(Ωr3)ϕ3=(2r1+r2+r3)ϕ4,χ2(ϕ)=r21+2r1r2+2r1r3+r2r3,χ1(ϕ)=r21r2r21r32r1r2r3,ϕ0=r21r2r3ϕ4ϕ4.(92)
    Therefore, the solution will be
    u3(x,t)={A0+A204B1r1A204B1(r1r2)(r1r3)2r1r2r3+(r3r2)cosh[(r1r2)(r1r3)12(JT2mλ2)B21T2p6A40(xλtξ0)]+B1r1(r1r2)(r1r3)2r1r2r3+(r3r2)cosh[(r1r2)(r1r3)12(JT2mλ2)B21T2p6A40(xλtξ0)]}12,(93)
    where θ1,θ2,θ4,A0,B1,p1 and p2 can be selected as free constants.

    Fourth solution. Let

    ±(ξξ0)=12(JT2mλ2)B21T2p6A40(r1r3)(r2r4)G(φ,σ),r1>r2>r3>r4,(94)
    where
    G(φ,σ)=φ0dψ1l2sin2ψ,φ=arcsin(r2r4)(Ωr1)(r1r4)(Ωr2),σ2=(r2r3)(r1r4)(r1r3)(r2r4)Ω=r2+(r1r2)(r4r2)r4r2+(r1r4)sn2[(r1r3)(r2r4)212(JT2mλ2)B21T2p6A40(ξξ0),(r2r3)(r1r4)(r1r3)(r2r4)],(95)
    Ω4+ϕ3ϕ4Ω3+χ2(ϕ)Ω2+χ1(ϕ)Ω+ϕ0ϕ4=(Γα1)(Γα2)(Γα3)(Γα4)(96)
    ϕ3=(r1+r2+r3+r4)ϕ4,χ2(ϕ)=r1r2+r1r3+r1r4+r2r3+r2r4+r3r4,χ1(ϕ)=r1r2r3r1r2r4r1r3r4r2r3r4,ϕ0=r1r2r3r4ϕ4.(97)
    Therefore, the solution will be
    u4(x,t)={A0+A204B1r2+A204B1(r1r2)(r4r2)r4r2+(r1r4)sn2[(r1r3)(r2r4)212(JT2mλ2)B21T2p6A40(xλtξ0),(r2r3)(r1r4)(r1r3)(r2r4)]+B1r2+(r1r2)(r4r2)r4r2+(r1r4)sn2[(r1r3)(r2r4)212(JT2mλ2)B21T2p6A40(xλtξ0),(r2r3)(r1r4)(r1r3)(r2r4)]}12.(98)

    Remark 1. If the modulus σ1, then the solution can be reduced to the solitary wave solution

    u5(x,t)={A0+A204B1r2+A204B1(r1r2)(r4r2)r4r2+(r1r4)tanh2[(r1r3)(r2r4)212(JT2mλ2)B21T2p6A40(xλtξ0)]+B1r2+(r1r2)(r4r2)r4r2+(r1r4)tanh2[(r1r3)(r2r4)212(JT2mλ2)B21T2p6A40(xλtξ0)]}12,(99)
    where r3=r4.

    Remark 2. If the modulus σ0, then the solution can be reduced to the solitary wave solution

    u6(x,t)={A0+A204B1r2+A204B1×(r1r2)(r4r2)r4r2+(r1r4)sin2[(r1r3)(r2r4)212(JT2mλ2)B21T2p6A40(xλtξ0)]+B1r2+(r1r2)(r4r2)r4r2+(r1r4)sin2[(r1r3)(r2r4)212(JT2mλ2)B21T2p6A40(xλtξ0)]}12,(100)
    where r2=r3.

    4.1.5. Set V

    Here we have

    A1=3/4A20p6A0p4+2μp2B1p6,ϕ1=1/2ϕ0(8A0p6+3p4)B1p6,ϕ2=3/2ϕ0(A20p6+2μp2)B21p6,ϕ3=38(A20p6A0p4+2μp2)ϕ0(8A0p6+3p4)B31p26,ϕ4=9(A20p6A0p4+2μp2)2ϕ016B41p26,ρ0=34ϕ0(JT2mλ2)T2B21p6.(101)
    Substituting these results into Eqs. (8) and (101), we get
    ±(ξξ0)=K0dΩΩ4+ϕ3ϕ4Ω3+ϕ2ϕ4Ω2+ϕ1ϕ4Ω+ϕ0ϕ4,K0=4/3(JT2mλ2)B21p6T2(A20p6A0p4+2μp2)2.(102)
    Integrating (102), the below solutions are achieved:

    First solution. Let

    ±(ξξ0)=4/3(JT2mλ2)B21p6T2(A20p6A0p4+2μp2)2Ωr1,Ω4+ϕ3ϕ4Ω3+χ2(ϕ)Ω2+χ1(ϕ)Ω+ϕ0ϕ4=(Ωr1)4,χ1(ϕ)=(64A0p6+24p4)B31p69(A20p6A0p4+2μp2)2,χ2(ϕ)=8/3(A20p6+2μp2)B21p6(A20p6A0p4+2μp2)2,χ3(ϕ)=2/3(8A0p6+3p4)B1A20p6A0p4+2μp2.(103)
    Therefore, the exact solution will be
    u1(x,t)={A0+3/4A20p6A0p4+2μp2B1p6r13/4A20p6A0p4+2μp2B1p6×4/3(JT2mλ2)B21p6T2(A20p6A0p4+2μp2)2xλtx0+B1r14/3(JT2mλ2)B21p6T2(A20p6A0p4+2μp2)2xλtx0}12,(104)
    where θ1,θ2,θ4,B1,p1 and p2 can be selected as free constants.

    Second solution. Let

    ±(ξξ0)=4/3(JT2mλ2)B21p6T2(A20p6A0p4+2μp2)2r1r2ln|Ωr1Ωr2|Ω=r2+(r1r2)4/3(JT2mλ2)B21p6T2(A20p6A0p4+2μp2)21exp((ξξ0)(r1r2)),(105)
    Ω4+ϕ3ϕ4Ω3+χ2(ϕ)Ω2+χ1(ϕ)Ω+ϕ0ϕ4=(Ωr1)2(Ωr2)2ϕ3=2(r1+r2)ϕ4,χ2(ϕ)=r21+4r1r2+r22,χ1(ϕ)=2r1r2(r1+r2),ϕ0=r21r22ϕ4.(106)
    Therefore, the solution will be
    u2(x,t)={A0+34A20p6A0p4+2μp2B1p6r2+34A20p6A0p4+2μp2B1p6×(r1r2)4/3(JT2mλ2)B21p6T2(A20p6A0p4+2μp2)21exp((xλtξ0)(r1r2))+B1r2+(r1r2)4/3(JT2mλ2)B21p6T2(A20p6A0p4+2μp2)21exp((xλtξ0)(r1r2))}12,(107)
    where θ1,θ2,θ4,B1,p1 and p2 can be selected as free constants.

    Third solution. Let

    ±(ξξ0)=12(JT2mλ2)B21T2p6A40(r1r2)(r1r3)ln|(r1r3)(Ωr2)(r1r2)(Ωr3)(r1r3)(Ωr2)+(r1r2)(Ωr3)|,(108)
    Ω=r1(r1r2)(r1r3)2r1r2r3+(r3r2)cosh[(r1r2)(r1r3)4/3(JT2mλ2)B21p6T2(A20p6A0p4+2μp2)2(xλtξ0)],(109)
    Ω4+ϕ3ϕ4Ω3+χ2(ϕ)Ω2+χ1(ϕ)Ω+ϕ0ϕ4=(Ωr1)2(Ωr2)(Ωr3)ϕ3=(2r1+r2+r3)ϕ4,χ2(ϕ)=r21+2r1r2+2r1r3+r2r3,χ1(ϕ)=r21r2r21r32r1r2r3,ϕ0=r21r2r3ϕ4ϕ4.(110)
    Therefore, the solution is given by
    u3(x,t)={A0+3/4A20p6A0p4+2μp2B1p6r13/4A20p6A0p4+2μp2B1p6×(r1r2)(r1r3)2r1r2r3+(r3r2)cosh[(r1r2)(r1r3)4/3(JT2mλ2)B21p6T2(A20p6A0p4+2μp2)2(xλtξ0)]+B1r1(r1r2)(r1r3)2r1r2r3+(r3r2)cosh[(r1r2)(r1r3)4/3(JT2mλ2)B21p6T2(A20p6A0p4+2μp2)2(xλtξ0)]}12,(111)
    where θ1,θ2,θ4,A0,B1,p1 and p2 can be selected as free constants.

    Fourth solution. Let

    ±(ξξ0)=12(JT2mλ2)B21T2p6A40(r1r3)(r2r4)G(φ,σ),r1>r2>r3>r4,(112)
    where
    G(φ,σ)=φ0dψ1l2sin2ψ,φ=arcsin(r2r4)(Ωr1)(r1r4)(Ωr2),σ2=(r2r3)(r1r4)(r1r3)(r2r4)(113)
    Ω=r2+(r1r2)(r4r2)r4r2+(r1r4)sn2[(r1r3)(r2r4)24/3(JT2mλ2)B21p6T2(A20p6A0p4+2μp2)2(ξξ0),(r2r3)(r1r4)(r1r3)(r2r4)],
    Ω4+ϕ3ϕ4Ω3+χ2(ϕ)Ω2+χ1(ϕ)Ω+ϕ0ϕ4=(Γα1)(Γα2)(Γα3)(Γα4)(114)
    ϕ3=(r1+r2+r3+r4)ϕ4,χ2(ϕ)=r1r2+r1r3+r1r4+r2r3+r2r4+r3r4,χ1(ϕ)=r1r2r3r1r2r4r1r3r4r2r3r4,ϕ0=r1r2r3r4ϕ4.(115)
    Therefore, the solution will be
    u4(x,t)={A0+3/4A02p6A0p4+2μp2B1p6r2+3/4A02p6A0p4+2μp2B1p6×(r1r2)(r4r2)r4r2+(r1r4)sn2(r1r3)(r2r4)24/3(JT2mλ2)B12p6T2(A02p6A0p4+2μp2)2(xλtξ0),(r2r3)(r1r4)(r1r3)(r2r4)+B1r2+(r1r2)(r4r2)r4r2+(r1r4)sn2(r1r3)(r2r4)24/3(JT2mλ2)B12p6T2(A02p6A0p4+2μp2)2(xλtξ0),(r2r3)(r1r4)(r1r3)(r2r4)12.(116)

    Remark 1. If the modulus σ1, then the solution can be reduced to the solitary wave solution

    u5(x,t)={A0+3/4A02p6A0p4+2μp2B1p6r2+3/4A02p6A0p4+2μp2B1p6×(r1r2)(r4r2)r4r2+(r1r4)tanh2(r1r3)(r2r4)24/3(JT2mλ2)B12p6T2(A02p6A0p4+2μp2)2(xλtξ0)+B1r2+(r1r2)(r4r2)r4r2+(r1r4)tanh2(r1r3)(r2r4)24/3(JT2mλ2)B12p6T2(A02p6A0p4+2μp2)2(xλtξ0)12,(117)
    where r3=r4.

    Remark 2. If the modulus σ0, then the solution can be reduced to the solitary wave solution

    u6(x,t)={A0+3/4A02p6A0p4+2μp2B1p6r2+3/4A02p6A0p4+2μp2B1p6×(r1r2)(r4r2)r4r2+(r1r4)sin2(r1r3)(r2r4)24/3(JT2mλ2)B12p6T2(A02p6A0p4+2μp2)2(xλtξ0)+B1r2+(r1r2)(r4r2)r4r2+(r1r4)sin2(r1r3)(r2r4)24/3(JT2mλ2)B12p6T2(A02p6A0p4+2μp2)2(xλtξ0)12,(118)
    where r2=r3.

    4.2. Case II: a=2,b=5 and c=1

    If we take a=2,b=5 and c=1 for Eqs. (7) and (8), then we obtain

    F(ξ)=A0+A1Ω+B1Ω1,(119)
    (F(ξ))2=ϕ5Ω5+ϕ4Ω4+ϕ3Ω3+ϕ2Ω2+ϕ1Ω+ϕ0ρ0+ρ1ΩA1B1Ω22,(120)
    where ϕ50 and ρ10. Solving the algebraic equation (12) yields different results.

    The different sets of categories of solutions are discussed in the following subsections.

    4.2.1. Set I

    Here we have

    A1=0,ϕ2=1/48A0p62(5A0ϕ02B1ϕ1)+6p4p6(5A0ϕ0B1ϕ1)+12p6ϕ0(p2+2μ)+9p42ϕ0B12p62,(121)

    ϕ4=1/89A0p4ϕ02S4+48μp62S28p63S012p4p62S118p4ϕ0S56p6S3B14p63ϕ0,

    S0=75A04ϕ0242A03B1ϕ0ϕ1+6A02B12ϕ12+B13ϕ3(3A0ϕ0B1ϕ1),
    S1=80A03ϕ0233A02B1ϕ0ϕ1+3A0B12ϕ12+B13ϕ0ϕ3,S2=13A02ϕ027A0B1ϕ0ϕ1+B12ϕ12,
    S3=A02ϕ02(52p2p6+81p42)2A0B1ϕ0ϕ1(14p2p6+9p42)+4B12p2p6ϕ12,

    S4=56μp628p2p69p42,S5=(4B1p6ϕ13p4ϕ0)(p2+2μ),
    ϕ5=1/8×A0(8A0p6ϕ02B1p6ϕ1+3p4ϕ0)(6A0p4p6S8+9A0ϕ0S64p62S76S9)B15p63ϕ0,
    S6=8μp64p2p63p42,S7=21A03ϕ06A02B1ϕ1+B13ϕ3,
    S8=16A0ϕ03B1ϕ1,S9=(2B1p6ϕ13p4ϕ0)(p2+2μ),ρ0=3/4ϕ0(JT2mλ2)T2B12p6,
    ρ1=3/8(8A0p6ϕ02B1p6ϕ1+3p4ϕ0)(JT2mλ2)B13p62T2.
    Substituting these results into Eqs. (8) and (121), we get
    ±(ξξ0)=ρ0ϕ5+ρ1ϕ5ΩdΩΩ5+ϕ4ϕ5Ω4+ϕ3ϕ5Ω3+ϕ2ϕ5Ω2+ϕ1ϕ5Ω+ϕ0ϕ5.(122)
    When Ω5+ϕ4ϕ5Ω4+ϕ3ϕ5Ω3+ϕ2ϕ5Ω2+ϕ1ϕ5Ω+ϕ0ϕ5=(Ωr1)5, then we have
    ±(ξξ0)=ρ0ϕ5+ρ1ϕ5ΩdΩ(Ωr1)2Ωr1=23ρ0ϕ5+ρ1ϕ5Ω32ρ0ϕ5+ρ1ϕ5r1(Ωr1)32(123)
    or
    Ω=ρ0ϕ5+r132ρ0ϕ5+ρ1ϕ5r1(ξξ0)3232ρ0ϕ5+ρ1ϕ5r1(ξξ0)32ρ1ϕ5.(124)
    Therefore, the solution will be
    u1(x,t)=A0+B132ρ0ϕ5+ρ1ϕ5r1(xλtξ0)32ρ1ϕ5ρ0ϕ5+r132ρ0ϕ5+ρ1ϕ5r1(xλtξ0)3212.(125)

    4.2.2. Set II

    Here we have

    B1=0,ϕ1=1/24A15p63ϕ0S712A03p4S2+12A02p62S13A03ϕ52(A0S3p63S5p4)+L1p62A0(8A0p6ϕ52A1p6ϕ4+3p4ϕ5)A14,(126)
    L1=12A02A12p2p62ϕ42+12A03A1p6ϕ4ϕ5S49A02p4ϕ5S6,S1=(4A0ϕ5A1ϕ4)2(A02p6+2μ),
    S2=p62(4A0ϕ5A1ϕ4)(7A0ϕ5A1ϕ4),S3=64p2p6+57p42,S4=8p2p6+3p42,
    S5=32μp616p2p63p42,S6=(p2+2μ)(4A1p6ϕ43p4ϕ5),S7=3A0ϕ5A1ϕ4,
    S8=(2μ+p2)(4A12p62ϕ42+3ϕ5(14A0p6ϕ54A1p6ϕ4+3p4ϕ5)p4),S9=(7A0ϕ52A1ϕ4)(4A0ϕ5A1ϕ4),
    S10=85A02ϕ5234A0A1ϕ4ϕ5+3A12ϕ42,S11=64μA0p6232A0p2p6256A0p42p69p43,

    S12=28μp614p2p69p42,

    ϕ2=8p63(A15ϕ0ϕ5+3A03S9)12A02p4p62S10+9A02ϕ52S1112A02A1p6ϕ4ϕ5S126A0S84A0A13p62(8A0p6ϕ52A1p6ϕ4+3p4ϕ5),

    ϕ3=1/48p62A0(5A0ϕ52A1ϕ4)+6p4p6(5A0ϕ5A1ϕ4)+12p6ϕ5(p2+2μ)+9p42ϕ5A12p62,

    ρ0=3/8(8A0p6ϕ52A1p6ϕ4+3p4ϕ5)(JT2mλ2)A13p62T2,ρ1=3/4ϕ5(JT2mλ2)T2A12p6.
    Substituting these results into Eqs. (8) and (126), we get
    ±(ξξ0)=ρ0ϕ5+ρ1ϕ5ΩdΩΩ5+ϕ4ϕ5Ω4+ϕ3ϕ5Ω3+ϕ2ϕ5Ω2+ϕ1ϕ5Ω+ϕ0ϕ5.(127)
    Therefore, the exact solution will be
    u1(x,t)=A0+A1ρ0ϕ5+r132ρ0ϕ5+ρ1ϕ5r1(xλtξ0)3232ρ0ϕ5+ρ1ϕ5r1(xλtξ0)32ρ1ϕ512.(128)

    4.2.3. Set III

    Here we have

    X=9p4+840μp6420p2p6+81p4270p6,A0=3X,A1=18p4X12μ+6p235B1p6,ϕ1=1/2ϕ0(20Xp6+3p4)B1p6,(129)
    ϕ2=3/10ϕ0(p4X4μ+2p2)B12p6,ϕ3=6ϕ0(X(1330μp6665p2p6+198p42)66p4(p2+2μ))1225B13p62,
    Y=p2+2μ,ϕ4=18ϕ0(p4X(837p42+3395p6)Y(770p6Y+279p42))42875B14p63,

    ϕ5=72ϕ0(X(4900μp62(μp2)+35p6(81p42Y+35p22p6)+729p44)9p4Y(70p6Y+27p42))1500625p64B15,

    ρ0=3/4ϕ0(JT2mλ2)T2B12p6,ρ1=3/2ϕ0X(JT2mλ2)p6B13T2.
    Substituting these results into Eqs. (8) and (126), we get
    ±(ξξ0)=ρ0ϕ5+ρ1ϕ5ΩdΩΩ5+ϕ4ϕ5Ω4+ϕ3ϕ5Ω3+ϕ2ϕ5Ω2+ϕ1ϕ5Ω+ϕ0ϕ5.(130)
    Hence, the exact solution will be
    u1(x,t)=27p4+3840μp6420p2p6+81p4270p618p4X12μ+6p235B1p6×ρ0ϕ5+r132ρ0ϕ5+ρ1ϕ5r1(xλtξ0)3232ρ0ϕ5+ρ1ϕ5r1(xλtξ0)32ρ1ϕ5+B132ρ0ϕ5+ρ1ϕ5r1(xλtξ0)32ρ1ϕ5ρ0ϕ5+r132ρ0ϕ5+ρ1ϕ5r1(xλtξ0)3212,X=9p4+840μp6420p2p6+81p4270p6.(131)

    4.2.4. Set IV

    Here we have

    A1=1/4A02B1,ϕ2=1/42A0p62(17A0ϕ08B1ϕ1)+6p4p6(5A0ϕ0B1ϕ1)+12p6ϕ0(p2+2μ)+9p42ϕ0B12p62,(132)

    ϕ3=1/84A02p62K13A0p4p6K2+12(2p6(4A0ϕ0B1ϕ1)+3p4ϕ0)(p2+2μ)54A0p42ϕ0B13p62,
    ϕ4=A02(A0p62(63A0ϕ016B1ϕ1)+6p4p6(8A0ϕ0B1ϕ1)+9p42ϕ0)16p62B14,ϕ5=A04(8A0p6ϕ02B1p6ϕ1+3p4ϕ0)32p6B15,
    ρ0=3/4ϕ0(JT2mλ2)T2B12p6,ρ1=3/8(8A0p6ϕ02B1p6ϕ1+3p4ϕ0)(JT2mλ2)B13p62T2.
    Substituting these results into Eqs. (8) and (132), we get
    ±(ξξ0)=ρ0ϕ5+ρ1ϕ5ΩdΩΩ5+ϕ4ϕ5Ω4+ϕ3ϕ5Ω3+ϕ2ϕ5Ω2+ϕ1ϕ5Ω+ϕ0ϕ5.(133)
    Therefore, the exact solution will be
    u1(x,t)=A0+1/4A02B1ρ0ϕ5+r132ρ0ϕ5+ρ1ϕ5r1(xλtξ0)3232ρ0ϕ5+ρ1ϕ5r1(xλtξ0)32ρ1ϕ5+B132ρ0ϕ5+ρ1ϕ5r1(xλtξ0)32ρ1ϕ5ρ0ϕ5+r132ρ0ϕ5+ρ1ϕ5r1(xλtξ0)3212.(134)

    4.2.5. Set V

    Here we have

    A1=34A02p6A0p4+2μp2B1p6,ϕ2=2A0p62(29A0ϕ08B1ϕ1)6p4p6(8A0ϕ0B1ϕ1)+6p6ϕ0(2μp2)9p42ϕ04B12p62,(135)

    ϕ3=3/84A02p62(6A0ϕ0B1ϕ1)+17A02p4p6ϕ0+(8A0p6ϕ04B1p6ϕ1+3p4ϕ0)(2μp2)+3A0p42ϕ0B13p62,

    ϕ4=3/16(A02p6A0p4+2μp2)(A0p62(67A0ϕ016B1ϕ1)3p4p6(17A0ϕ02B1ϕ1)+3p6ϕ0(2μp2)9p42ϕ0)B14p63,

    ϕ5=9(A02p6A0p4+2μp2)2(8A0p6ϕ02B1p6ϕ1+3p4ϕ0)32B15p63,

    ρ0=3/4ϕ0(JT2mλ2)T2B12p6,ρ1=3/8(8A0p6ϕ02B1p6ϕ1+3p4ϕ0)(JT2mλ2)B13p62T2.
    Substituting these results into Eqs. (8) and (135), we get
    ±(ξξ0)=ρ0ϕ5+ρ1ϕ5ΩdΩΩ5+ϕ4ϕ5Ω4+ϕ3ϕ5Ω3+ϕ2ϕ5Ω2+ϕ1ϕ5Ω+ϕ0ϕ5.(136)
    Therefore, the exact solution will be
    u1(x,t)=A0+A1=3/4A02p6A0p4+2μp2B1p6×ρ0ϕ5+r132ρ0ϕ5+ρ1ϕ5r1(xλtξ0)3232ρ0ϕ5+ρ1ϕ5r1(xλtξ0)32ρ1ϕ5+B132ρ0ϕ5+ρ1ϕ5r1(xλtξ0)32ρ1ϕ5ρ0ϕ5+r132ρ0ϕ5+ρ1ϕ5r1(xλtξ0)3212.(137)

    4.3. Results

    By selecting the appropriate values for the parameters, we were able to generate the desired types of solutions that indicate wave discrepancy. The analytical solutions are coded in Maple and the parametric and sensitivity analyses are carried out using the codes. The parametric results are presented in Figs. 110. The results from the simulations show that through the inherent properties of auxiliary parameters for the adjustment and control of region and rate of convergence of approximate series solutions, generalized trial equation scheme and generalized G-expansion method have proven to be very efficient and capable techniques for handling the nonlinear engineering problems for wider ranges of parameters. The importance of this study lies in the fact that it can serve as a base for the experimental work that we want to undertake on the plasma physics and crystal lattice theory. The traveling-wave transformation was used along with the extended sinh-Gordon equation expansion technique and the Riccati equation method to construct the soliton and other wave solutions of the thin-film ferroelectric material equation.27 In addition, dark soliton and cnoidal waves that have not been observed in ferroelectrics were obtained, and a bright soliton has been found for TFFME.31 The modified simple equation method and Riccati–Bernoulli sub-ODE method were used in TFFME to investigate the waves propagating through ferroelectric materials.32 Moreover, the Paul–Painlevé approach was used to achieve the optical soliton solutions of the thin-film ferroelectric material equation.33 According to the existing literature and obtained results, we understand there are plenty of solutions including more types of obtained solutions.

    5. Conclusion

    To conclude, the solitary wave solutions by utilizing the generalized trial equation scheme were analytically constructed, and we also noticed that the equation was nonintegrable. The impact of wave motion in plasma on the physical parameters including speed and amplitudes of solitary waves was focused. Subsequently, several exact explicit solutions to this problem have been investigated utilizing these improvements and symbolic computation. In particular, four forms of function solutions, including soliton, kink–soliton, singular-soliton and periodic wave solutions, were studied. Plenty of exact solutions for the two cases were found. Via graphical illustrations by using the considered methods, the dynamical behavior of results was investigated. Many other nonlinear evolution equations, including coupled ones, can be solved using this technique. Along with the scientific derivation for the analytical findings, the outcomes were graphically displayed to help identify the dynamical aspects easily. Theoretical insights reported here may be considered helpful for future experimental studies. Moreover, various important remarks about the physical meanings of solutions were presented. From these results, it may be seen that MEJM and EEM are power tools to solve such nonlinear partial models arising in applied and engineering sciences. In the future, we can further study their soliton solutions, rogue wave solutions, solitary waves, symmetry, etc. We utilized the Maple program package to carry out the computations and confirm every outcome.

    Conflict of Interest

    Authors declare they have no competing interests regarding the publication of this paper.

    Acknowledgments

    The researchers would like to acknowledge the Deanship of Scientific Research, Taif University, for funding this work.

    Also, this work was supported by the Jilin Province Science and Technology Association, “The Fourth Batch of Young Talent Support Project”, Grant No. QT202014.

    You currently do not have access to the full text article.

    Recommend the journal to your library today!