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Research PaperOpen Access

Some subvarieties of semirings variety COSn

    https://doi.org/10.1142/S2811007223500104Cited by:0 (Source: Crossref)

    Abstract

    Green’s ∗-relations on semirings satisfying additional identities xnx and 2(x+y)2x+2y are studied. Equivalent characterizations of +, +, +𝒟, +, +, +, +𝒟 and + are obtained and equivalent conditions are given for the above relations to be congruences. It is proved that semiring classes determined by these congruences are varieties.

    1. Introduction

    A semiring (S,+,) is an algebra of type (2,2) satisfying the following additional identities:

    x+(y+z)(x+y)+z,x(yz)(xy)z,z(x+y)zx+zy,(x+y)zxz+yz.

    A variety of algebras is a class of algebras of the same type that is closed under the formation of subalgebras, homomorphic images and direct products (see [1]). A class, by Birkhoff’s theorem, of algebras of the same type is a variety if and only if it is an equational class. Obviously, all semirings form a variety.

    Since semirings are two semigroups on the same nonempty set connected by distributive laws, the results and methods in algebraic theory of semigroups can be applied in the study of semirings (see [5,11]). Some scholars studied different completely regular semirings by Green’s relations of semigroups. Pastijn and Zhao [10] characterized idempotent semiring varieties and proved that Green’s 𝒟-relation on an idempotent semiring is the least lattice congruence. Zhao et al. [18,17] studied idempotent semiring varieties using Green’s relations on additive reduct and multiplicative reduct. Damljanović et al. [4] obtained congruence openings of Green’s relations on the additive reduct of a semiring. Wang and Shao [13] showed that SRn(N+S) is isomorphic to a subsemiring of S/σ×S/+. Cheng and Shao [2,3] defined and studied several varieties of multiplicative idempotent semirings by congruence openings of multiplicative Green’s relations on a semiring. Xian et al. [16] gave equivalent characterization of Green’s relations on the additive (respectively, multiplicative) reduct of the semiring in COS+3 and obtained the sufficient and necessary conditions which make intersections and joins of these binary relations be congruences. Xian et al. [15] considered the closure congruences of Green’s relations on the additive (respectively, multiplicative) reduct of semirings, and several varieties of semirings determined by the closure congruences are characterized. Wang et al. [14] gave some equivalent descriptions of intersections between Green’s relations on the additive reduct and Green’s relations on multiplicative reduct of a semiring with additional identities xnx, (2n1)xx, (x+y)n1xn1+yn1 and (xy)n1xn1yn1 and obtained the necessary conditions which make these binary relations be congruences.

    With continuous research, some scholars have also paid attention to some semirings whose additive reducts are not completely regular. As a generalization of completely regular semiring, Maity and Ghosh [7, Theorem 3.10] defined quasi completely regular semiring, which is semiring (S,+,) satisfying the following conditions: For every aS, there exists a positive integer n such that na is completely regular, that is,

    na=na+x+na,na+x=x+na,na+x=na(na+x),
    for a suitable element xS. Maity and Ghosh [12,7] showed that a semiring is quasi completely regular if and only if every +-class is a quasi skew-ring. Moreover, they [8,9] investigated the congruence generated by a special equivalence relation on quasi completely regular semirings with and without the special conditions like being quasi-orthodox and characterized the least completely regular semiring congruence on quasi completely regular semirings.

    In this paper, we denote by COSn the semiring variety satisfying the following additional identities for n2:

    xnx,2(x+y)2x+2y.
    For any SCOSn and aS, it is easy to check 2a=2na and so 2a is a completely regular element in (S,+). Hence, (S,+) is completely π-regular (see [7]). Obviously, (S,) is completely regular. Let E+(S) (respectively, E(S)) denote the set of all idempotents of (S,+) (respectively, (S,)) and m=2n2. We can easily prove that E+(S)={ma:aS} and E(S)={an1:aS}.

    In Sec. 2, as a generalization of Green’s relations, we recall Green’s ∗-relations and obtain some properties. In Sec. 3, we give characterizations of + (respectively, +, +𝒟, +) as a congruence on semirings and prove that semiring classes determined by these congruences are subvarieties of COSn. In Sec. 4, we describe an equivalence condition that + (respectively, +, +𝒟, +) is a congruence on a semiring in COSn and show that semiring classes determined by these congruences are also subvarieties of COSn.

    For other notation and terminology, we use in this paper the reader is referred to [7, 13, 17].

    2. Preliminaries

    Let (S,+,) be a semiring. Generally, we denote Green’s relations on the additive (respectively, multiplicative) reduct (S,+) (respectively, (S,)) by +, +, 𝒟+, + and 𝒥+ (respectively, , , 𝒟, and 𝒥). We recall equivalence relations defined by Maity and Ghosh [6, Definition 3.5] as follows:

    a+bif and only ifra+sb,a+bif and only ifra+sb,a𝒥+bif and only ifra𝒥+sb,
    where r and s are the smallest positive integers such that ra and sb are additively regular. They are called Green’s ∗-relations. If SCOSn, then, for every aS, 2a is a additively regular element. So, we have the following.

    Definition 2.1. Let SCOSn and a,bS. Then

    a+b2a+2b,ab2a2b,a+b2a+2b,ab2a2b,a𝒟+b2a𝒟+2b,a𝒟b2a𝒟2b,a+b2a+2b,ab2a2b.

    Let S={2a:aS}. Obviously, S is a completely regular subsemiring of S. Thus, by [11, II, Theorem 3.6], we have the following.

    Theorem 2.1. Let SCOSn and a,bSThen

    a+b{2a=2a+mb,2b=2b+ma,ab{2a=2abn1,2b=2ban1,a+b{2a=2a+mb,2b=2b+ma,ab{2a=2bn1a,2b=2an1b,a𝒟+b{2a=2a+m(b+a),2b=m(b+a)+2b,a𝒟b{2a=2a(ba)n1,2b=2(ba)n1b,a+bma=mb,ab(2a)n1=(2b)n1.

    Lemma 2.1. Let SCOSnThen (E+(S),+,) is a subsemiring of S. In fact, for every a,bSwe have

    m(a+b)=ma+mb.

    Proof.. Let SCOSn. For any a,bS, take f=(a+b)n1(ma+mb). On the one hand, f=(a+b)n1(ma)+(a+b)n1(mb)=m(a+b)n1(a+b)=m(a+b). On the other hand, from ma,mbE+(S), we have

    f=(a+b)n2(a+b)(ma+mb)=(a+b)n2(a+b)(m2a+m2b)=(a+b)n2(ma+mb)2=ma+mb.
    Thus, m(a+b)=ma+mb. □

    By Lemma 2.1, we have the following.

    Lemma 2.2. Let SCOSn and a,bSThen

    (ma+2b)k=m(a+b)k+2kbk,(2a+mb)k=2kak+m(a+b)k,
    where k is a positive integer.

    Proof. Let SCOSn. For any a,bS. In the first equality, the claim obviously holds when k=1. Assume now that this equality holds for k1 and then, by Lemma 2.1,

    (ma+2b)k=(ma+2b)(ma+2b)k1=(ma+2b)(m(a+b)k1+2k1bk1)=m(ma(a+b)k1+2k1abk1+2b(a+b)k1)+2kbk=m(a(a+b)k1+abk1+b(a+b)k1+bbk1)+2kbk=m(a+b)((a+b)k1+bk1)+2kbk=m(a+b)k+2kbk,
    since the last term of (a+b)k1 is bk1. Similarly, we can prove that the second equality holds. □

    Immediately, we have the following results.

    Theorem 2.2. Let SCOSn and a,bSThen

    m(a+b)=m(a+b+(a+b)(ba+b2)n1),m(a+b)=m(a+b+(ba+b2)n1(a+b)),m(a+b)=m((a+b)(a2+ba)n1+a+b),m(a+b)=m((a2+ba)n1(a+b)+a+b).

    Proof. Let f=(2a+mb)((ma+2b)(2a+mb))n1. By Lemma 2.1, mf=m(a+b), since ma,mbE+(S). By Lemma 2.2, we have

    f=(2a+mb)(m(a2+ab)+2(2ba+mb2))n1=(2a+mb)(m(a2+ab+2ba+mb2)n1+2n1(2ba+mb2)n1)=m(2a+mb)(a+b)n1+(2a+mb)(2n1(ba)n1+m(ba+b2)n1)=m(a+b)+2a(ba)n1+m(a(ba+b2)n1+b(ba)n1+b(ba+b2)n1)=m(a+b)+2a(ba)n1+m(a+b)(ba+b2)n1.
    This shows that mf=m(a+b+(a+b)(ba+b2)n1). Therefore, the first equality holds. Note that if we rewrite f=(2a+mb)(2(ma2+2ba)+m(ab+b2))n1, then
    f=ma(a2+ba)n1+2a(ba)n1+m(b(a2+ba)n1+a+b).
    This shows that mf=m((a+b)(a2+ba)n1+a+b). Therefore, the third equation holds. From f=((ma+2b)(2a+mb))n1(ma+2b) we can prove that the other equalities hold. □

    3. Some of the Subvarieties Associated with +

    In this section, we give sufficient and necessary conditions that +, +, +𝒟 and + are congruences on S and prove that the classes of semirings determined by these congruences are subvarieties of COSn. By Theorem 2.1, we have

    Lemma 3.1. Let SCOSn and a,bSThen

    (i)

    a+b(u,vS)2a=2u+mv, 2b=mu+2v,

    (ii)

    ab(u,vS)2a=2uvn1un1, 2b=2vun1,

    (iii)

    ab(u,vS)2a=2un1vn1u, 2b=2un1v,

    (iv)

    a𝒟b(u,vS)2a=2u(vu)n1, 2b=2(vu)n1v,

    (v)

    ab(u,vS)2a=2(vu)n1u(vu)n1, 2b=2(vu)n1v(vu)n1.

    Proof. We only prove (iv), and others can be proved similarly. Let u=a, v=b. If a𝒟b, then 4vu=4ba in R2bL2a by [5, Proposition 2.3.7]. Hence, by [5, Proposition 2.3.3], 2a=2u(vu)n1 and 2b=2(uv)n1v. Conversely, if u,vS and let 2a=2u(vu)n1, 2b=2(uv)n1v, then 2a=2a(ba)n1 and 2b=2(ba)n1b. Therefore, by Theorem 2.1, 2a𝒟2b. □

    The conclusions with respect to intersections between above Green’s ∗-relations are given by the following lemma.

    Lemma 3.2. Let SCOSn and a,bSThen

    (i)

    a(+)b(u,vS){2a=2ũ+m,ũ=uvn1un1,2b=mũ+2,=vun1,

    (ii)

    a(+)b(u,vS){2a=2ũ+m,ũ=un1vn1u,2b=mũ+2,=un1v,

    (iii)

    a(+𝒟)b(u,vS){2a=2ũ+m,ũ=u(vu)n1,2b=mũ+2,=(vu)n1v,

    (iv)

    a(+)b(u,vS){2a=2ũ+m,ũ=(vu)n1u(vu)n1,2b=mũ+2,=(vu)n1v(vu)n1.

    Proof. We only prove (iii), and others can be proved similarly. If a(+𝒟)b, then 2a=2a(ba)n1, 2b=2(ba)n1b, ma=mb by Theorem 2.1. Let u=a, v=b. Then

    2u(vu)n1+m(vu)n1v=2a(ba)n1+m(ba)n1b=2a+mb=2a
    and
    mu(vu)n1+2(vu)n1v=ma(ba)n1+2(ba)n1b=ma+2b=2b.
    Conversely, if 2a=2u(vu)n1+m(vu)n1v, 2b=mu(vu)n1+2(vu)n1v, then a+b. Let ũ=u(vu)n1, =(vu)n1v. Hence, by Theorem 2.1 and Lemma 3.1, 2ũ=2ũ(ũ)n1 and 2=2(ũ)n1. By Lemma 2.2 and Theorem 2.2, we have
    (2a)((2b)(2a))n1=(2ũ+m)((mũ+2)(2ũ+m))n1=(2ũ+m)(m(ũ+)n1+2n1(2ũ+m2)n1)=m(ũ+)+2ũ(ũ)n1+m(ũ++(ũ+)(ũ+2)n1)=m(ũ+)+2ũ+m=2a
    and
    ((2b)(2a))n1(2b)=((mũ+2)(2ũ+m))n1(mũ+2)=(m(ũ+)n1+2n1(2ũ+m2)n1)(mũ+2)=m((ũ+)+(ũ+2)n1ũ)+2(ũ)n1+m(ũ+2)n1=mũ+2+m(ũ+)=2b.
    Thus a𝒟b. □

    Now, we can establish the following theorem.

    Theorem 3.1. Let SCOSnThen

    (i)

    +Con(S) if and only if S satisfies the following identities:

    z(2˜x+m)(z(m˜x+2))n1z(2˜x+m),(2z+2˜x+m)(2z+m˜x+2)n12z+2˜x+m,(2˜x+m+2z)(m˜x+2+2z)n12˜x+m+2z,
    where ˜x=xyn1xn1=yxn1.

    (ii)

    +Con(S) if and only if S satisfies the following identities:

    ((m˜x+2)z)n1(2˜x+m)z(2˜x+m)z,(2z+m˜x+2)n1(2z+2˜x+m)2z+2˜x+m,(m˜x+2+2z)n1(2˜x+m+2z)2˜x+m+2z,
    where ˜x=xn1yn1x, =xn1y.

    (iii)

    +𝒟Con(S) if and only if S satisfies the following identities:

    (2z+2˜x+m)((2z+m˜x+2)(2z+2˜x+m))n12z+2˜x+m,(2˜x+m+2z)((m˜x+2+2z)(2˜x+m+2z))n12˜x+m+2z,
    where ˜x=x(yx)n1=(yx)n1y.

    (iv)

    +Con(S) if and only if S satisfies the following identities:

    (2z+2˜x+m)n1(2z+m˜x+2)n1,(2˜x+m+2z)n1(m˜x+2+2z)n1,
    where ˜x=(yx)n1x(yx)n1=(yx)n1y(yx)n1.

    Proof. We only prove (i), and others can be proved similarly. If +Con(S), then, by Lemma 3.2, (2x+my)(+)(mx+2y) where x=abn1an1, y=ban1 for all a,b,cS. Hence c(2x+my)c(mx+2y), (2c+2x+my)(2c+mx+2y) and (2x+my+2c)(mx+2y+2c), i.e.

    c(2x+my)(c(mx+2y))n1=c(2x+my),(2c+2x+my)(2c+mx+2y)n1=2c+2x+my,(2x+my+2c)(mx+2y+2c)n1=2x+my+2c.
    Thus, S satisfies the corresponding identities above.

    Conversely, suppose a(+)b for any a,bS. If S satisfies the corresponding identities, then, by Lemma 3.2, there exist u,vS such that 2a=2x+my, 2b=mx+2y where x=uvn1un1, y=vun1. Thus, for all cS,

    c(2x+my)(c(mx+2y))n1=c(2x+my),(2c+2x+my)(2c+mx+2y)n1=2c+2x+my,(2x+my+2c)(mx+2y+2c)n1=2x+my+2c,
    i.e. 2(ca)(cb)n1=2ca, (2c+2a)(2c+2b)n1=2c+2a and (2a+2c)(2b+2c)n1=2a+2c. Dually, 2(cb)(ca)n1=2cb, (2c+2b)(2c+2a)n1=2c+2b and (2b+2c)(2a+2c)n1=2b+2c. That is to say, cacb, (c+a)(c+b) and (a+c)(b+c). Hence, is a left congruence on (S,) and a congruence on (S,+). Since is a right congruence on (S,), it follows that is a congruence on S. Thus, +Con(S). □

    By Theorem 3.1, semiring classes {SCOSn:+Con(S)}, {SCOSn:+Con(S)}, {SCOSn:+𝒟Con(S)} and {SCOSn:+Con(S)} are varieties. If n=2, then this result on S is the same as Theorem 2.3 in [16].

    A useful further specialization of this result is provided by the following corollary.

    Corollary 3.1. Let SCOSnThen

    +=ΔS2˜x+mm˜x+2,˜x=xyn1xn1,=yxn1,+=ΔS2˜x+mm˜x+2,˜x=xn1yn1x,=xn1y,+𝒟=ΔS2˜x+mm˜x+2,˜x=x(yx)n1,=(yx)n1y,+=ΔS2˜x+mm˜x+2,˜x=(yx)n1x(yx)n1,=(yx)n1y(yx)n1.

    Thus, semiring classes {SCOSn:+=Δ}, {SCOSn:+=Δ}, {SCOSn:+𝒟=Δ} and {SCOSn:+=Δ} are varieties.

    4. Some New Subvarieties Associated with Green’s ∗-relations

    In this section, we describe some new subvarieties of COSn by identities. The characterizations for +, +, +𝒟 and + are given by the following lemma.

    Lemma 4.1. Let SCOSnThen

    +=++,+=++,+𝒟=+𝒟+,+=++.

    Proof. We only prove the third equality. It is obvious that +𝒟++𝒟. To show that +𝒟+𝒟+, we need to verify 𝒟+𝒟+𝒟+. If a𝒟+𝒟b for any a,bS, then there exist c,dS such that a𝒟c+d𝒟b. Certainly, 2a=2a(ca)n1+2a(da)n1. Since 𝒟 is a congruence on (S,), it follows that 2(da)n1d𝒟2(bc)n1b by 2a𝒟2c, 2b𝒟2d. Therefore, by Lemma 3.1, 2a+2a(da)n1𝒟2(da)n1d𝒟2(bc)n1b+2b(db)n1=2b, i.e. a+𝒟+b. This implies that 𝒟+𝒟+𝒟+. So, it is easy to check that +𝒟+ is an equivalence containing + and 𝒟. Thus, +𝒟+𝒟+ and so +𝒟=+𝒟+. Other equalities can be proved similarly. □

    Further characterizations are available.

    Lemma 4.2. Let SCOSn and a,bSThen

    (i)

    a(+)ba+abn1, b+ban1,

    (ii)

    a(+)ba+bn1a, b+an1b,

    (iii)

    a(+𝒟)ba+a(ba)n1, b+(ba)n1b,

    (iv)

    a(+)ban1+bn1.

    Proof. We only prove (iii) and others can be proved similarly. If a(+𝒟)b for any a,bS, then there exist c,dS such that a+c𝒟d+b by Lemma 4.1. So, by Theorem 2.1, ma=mc=mc(dc)n1=mc((md)(mc))n1=ma(ba)n1. Thus, a+a(ba)n1. Similarly, b+(ba)n1b. Conversely, if a+a(ba)n1 and b+(ba)n1b, then, by Lemma 3.1, a+a(ba)n1𝒟(ba)n1b+b. Thus, by Lemma 4.1, a(+𝒟)b. □

    Lemma 4.3. Let SCOSnThen

    +Con(S)(S/+)Con(S/+),+Con(S)(S/+)Con(S/+),+𝒟Con(S)𝒟(S/+)Con(S/+),+Con(S)(S/+)Con(S/+).

    The characterization of (respectively, , 𝒟, ) is given by the following lemma.

    Lemma 4.4. Let SCOSnThen

    (i)

    Con(S) if and only if S satisfies the following identities:

    2zxyn1xn1(zyxn1)n12zxyn1xn1,2(z+xyn1xn1)(z+yxn1)n12z+2xyn1xn1,2(xyn1xn1+z)(yxn1+z)n12xyn1xn1+2z.

    (ii)

    Con(S) if and only if S satisfies the following identities:

    2(xn1yz)n1xn1yn1xz2xn1yn1xz,2(z+xn1y)n1(z+xn1yn1x)2z+2xn1yn1x,2(xn1y+z)n1(xn1yn1x+z)2xn1yn1x+2z.

    (iii)

    𝒟Con(S) if and only if S satisfies the following identities:

    2(z+x(yx)n1)((z+(yx)n1y)(z+x(yx)n1))n12z+2x(yx)n1,2(x(yx)n1+z)(((yx)n1y+z)(x(yx)n1+z))n12x(yx)n1+2z.

    (iv)

    Con(S) if and only if S satisfies the following identities:

    (2z+2(yx)n1x(yx)n1)n1(2z+2(yx)n1y(yx)n1)n1,(2(yx)n1x(yx)n1+2z)n1(2(yx)n1y(yx)n1+2z)n1.

    Proof. We only prove (i) and others can be proved similarly. By Lemma 3.1, 2abn1an12ban1 for all a,bS. If Con(S), then

    2cabn1an12cban1,2(c+abn1an1)2(c+ban1),2(abn1an1+c)2(ban1+c),
    for all cS, i.e.
    2cabn1an1(2cban1)n1=2cabn1an1,2(c+abn1an1)(c+ban1)n1=2(c+abn1an1),2(abn1an1+c)(ban1+c)n1=2(abn1an1+c).
    Thus, S satisfies the corresponding identities above.

    Conversely, let ab for any a,bS. If S satisfies the corresponding identities, then there exist u,vS such that a=uvn1un1 and b=vun1 by Lemma 3.1. Also, for all cS,

    2cuvn1un1(2cvun1)n1=2cuvn1un1,2(c+uvn1un1)(c+vun1)n1=2(c+uvn1un1),2(uvn1un1+c)(vun1+c)n1=2(uvn1un1+c).
    i.e. 2(ca)(cb)n1=2ca, 2(c+a)(c+b)n1=2(c+a) and 2(a+c)(b+c)n1=2(a+c). Dually, 2(cb)(ca)n1=2cb, 2(c+b)(c+a)n1=2(c+b) and 2(b+c)(a+c)n1=2(b+c). That is to say, cacb, (c+a)(c+b) and (a+c)(b+c). Thus, is a left congruence on (S,) and a congruence on (S,+). But is a right congruence on (S,), it follows that is a congruence on S. □

    By Lemma 4.4, semiring classes {SCOSn:Con(S)}, {SCOSn:Con(S)}, {SCOSn:𝒟Con(S)} and {SCOSn:Con(S)} are varieties.

    By Lemmas 4.3 and 4.4, we obtain the following theorem.

    Theorem 4.1. Let SCOSnThen

    (i)

    +Con(S) if and only if S satisfies the following identities:

    mzxyn1xn1(zyxn1)n1mzxyn1xn1,m(z+xyn1xn1)(z+yxn1)n1mz+mxyn1xn1,m(xyn1xn1+z)(yxn1+z)n1mxyn1xn1+mz.

    (ii)

    +Con(S) if and only if S satisfies the following identities:

    m(xn1yz)n1xn1yn1xzmxn1yn1xz,m(z+xn1y)n1(z+xn1yn1x)mz+mxn1yn1x,m(xn1y+z)n1(xn1yn1x+z)mxn1yn1x+mz.

    (iii)

    +𝒟Con(S) if and only if S satisfies the following identities:

    m(z+x(yx)n1)((z+(yx)n1y)(z+x(yx)n1))n1mz+mx(yx)n1,m(x(yx)n1+z)(((yx)n1y+z)(x(yx)n1+z))n1mx(yx)n1+mz.

    (iv)

    +Con(S) if and only if S satisfies the following identities:

    m(z+(yx)n1x(yx)n1)n1m(z+(yx)n1y(yx)n1)n1,m((yx)n1x(yx)n1+z)n1m((yx)n1y(yx)n1+z)n1.

    Proof. We only prove (i) and others can be proved similarly. If +Con(S), then, by Lemma 4.3

    cabn1an1+cabn1an1(cban1)n1,(c+abn1an1)+(c+abn1an1)(c+ban1)n1,(abn1an1+c)+(abn1an1+c)(ban1+c)n1,
    for all a,b,cS, i.e.
    mcabn1an1(cban1)n1=mcabn1an1,m(c+abn1an1)(c+ban1)n1=mc+mabn1an1,m(abn1an1+c)(ban1+c)n1=mabn1an1+mc.
    Thus, S satisfies the corresponding identities above.

    Conversely, if S satisfies the corresponding identities, then

    c(abn1an1)+c(abn1an1)(c(ban1))n1,(c+abn1an1)+(c+abn1an1)(c+ban1)n1,(abn1an1+c)+(abn1an1+c)(ban1+c)n1,
    for all a,b,cS. Hence, by Lemma 4.3, +Con(S). □

    From Theorem 4.1, semiring classes {SCOSn:+Con(S)}, {SCOSn:+Con(S)}, {SCOSn:+𝒟Con(S)} and {SCOSn:+Con(S)} are varieties.

    We immediately have the following corollary.

    Corollary 4.1. Let SCOSnThen

    +=Smxyn1mx,+=Smyn1xmx,+𝒟=Smx(yx)n1mx,+=Smyn1mxn1.

    Semiring classes {SCOSn:+=}, {SCOSn:+=}, {SCOSn:+𝒟=} and {SCOSn:+=} are varieties.

    ORCID

    Yilin Mao  https://orcid.org/0009-0007-2781-2817

    Yong Shao  https://orcid.org/0000-0003-3365-8987

    Yanliang Cheng  https://orcid.org/0009-0003-6862-9446